How many coulombs are required to reduce 1 mole of Br₂ to Br⁻ ? (F = 96500 C/mol)
Br₂ + 2e⁻ → 2Br⁻ . 1 mol Br₂ requires 2F. Charge = 2 × 96500 = 193000 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrochemical Cells - Galvanic Cells and Electrode Potential