7 public questions tagged with this topic.
In CH₂=CHCH₂Br , the carbon attached to Br has four single bonds (to Br, H, H, and CH=CH₂ ), making it sp³ hybridized.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
E°cell = 1.07 - (-0.40) = 1.47 V . Ecell = 1.47 - (0.059/2) log ([Cd²⁺][Br⁻]²/1) = 1.47 - 0.0295 log (0.005 × 0.0001) = 1.47 + 0.103 = 1.573 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant
E°cell = 1.07 - (-0.28) = 1.35 V . Ecell = 1.35 - (0.059/2) log ([Co²⁺][Br⁻]²/1) = 1.35 - 0.0295 log (0.01 × 0.0025) = 1.35 + 0.073 = 1.423 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant
Let Br = x. F = -1. Equation: x + 3(-1) = 0, x - 3 = 0, x = +3.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
In BrF₅ , bromine has 6 electron pairs (5 bonding, 1 lone), requiring sp³d² hybridization, forming a square pyramidal shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
Halogens belong to group 17. Among O, S, Se, and Br, only Br is in group 17, making it a halogen.
Ref: NCERT Class 11 Chemistry > Chapter 3: Classification of Elements and Periodicity in Properties > Topic: Nomenclature of Elements with Atomic Number >100
Electron gain enthalpy becomes less negative down group 17 due to increasing atomic size. Cl has the most negative value due to optimal nuclear charge and size, followed by F (less negative due to electron repulsion in its compact 2p orbitals), then Br. Order: Cl > F > Br.
Ref: NCERT Class 11 Chemistry > Chapter 3: Classification of Elements and Periodicity in Properties > Topic: Electron Gain Enthalpy and Electronegativity and Valency
