A 0.05 M solution of a weak base B has a pH of 10. What is its Kb ?
pH = 10 , pOH = 14 - 10 = 4 , [OH-] = 10⁻⁴ . For B + H₂O BH+ + OH- , Kb = ([OH-]²/[B]) = ((10⁻⁴)²/0.05) = (10⁻⁸/0.05) = 2.0 × 10⁻⁷ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
