10 public questions tagged with this topic.
Pa = ρgh. ρ = 13.6×103kg/m3, g = 10m/s2, h = 0.75m. Pa = 13.6×103×10×0.75 = 1.02×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.02 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Atmospheric pressure decreases with altitude as the weight of the air column above reduces, a fundamental concept in the chapter’s discussion of pressure variation. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It decreases with altitude. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
The barometer measures atmospheric pressure (Pa = ρgh). During a storm, atmospheric pressure drops, reducing the force supporting the mercury column, causing its height to decrease, as noted in the chapter.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.43kg/m3, g = 9.8m/s2, h = 1.8m. P = 1.01×105+1.43×9.8×1.8 = 1.01×105+25.21 = 1.0102521×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.01 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
A barometer measures atmospheric pressure by balancing it with the weight of a liquid column (Pa = ρgh), typically mercury due to its high density, which shortens the column height.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Atmospheric pressure is the weight of the air column per unit area above a point, extending to the top of the atmosphere, as it results from the gravitational force acting on the air mass, as described in the chapter.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Atmospheric pressure is the weight of the air column above a point. As altitude increases, the height and mass of the air column decrease, reducing the pressure exerted at higher elevations.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 3.6m. P = 1.01×105+13.6×103×9.8×3.6 = 1.01×105+479808 = 5.80808×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.8 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
At lower altitudes, the air column above is taller and heavier, increasing atmospheric pressure (Pa = ρgh), which raises the height of the mercury column in the barometer to balance the greater external pressure.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.06×103kg/m3, g = 9.8m/s2, h = 2.8m. P = 1.01×105+1.06×103×9.8×2.8 = 1.01×105+29094.4 = 1.300944×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.30 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
