6 public questions tagged with this topic.
Thionyl chloride ( SOCl₂ ) reacts with alcohols to form alkyl chlorides, producing SO₂ and HCl , both gases, making it preferred for pure product formation.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms
PCl₅ converts 2-pentanol ( CH₃CH₂CH₂CHOHCH₃ ) to 2-chloropentane ( CH₃CH₂CH₂CHClCH₃ ) via substitution.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
PCl₅ reacts with 1-butanol ( CH₃CH₂CH₂CH₂OH ) to form 1-chlorobutane ( CH₃CH₂CH₂CH₂Cl ) with POCl₃ and HCl as byproducts.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Classification and Nomenclature and Isomerism of Haloalkanes
Cleavage at CH₂Cl forms CH₃CH₂CH₂CH₂CH₂⁺ (primary). A hydride shift to CH₃CH₂CH₂CH⁺CH₃ (secondary) increases stability via hyperconjugation.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Cleavage at C-Cl forms CH₃CH₂CH₂CH⁺CH₃ (secondary). A hydride shift to CH₃CH₂CH⁺CH₂CH₃ (secondary) is equally stable, but +I effect from alkyl groups favors it slightly more.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Heterolytic cleavage of CH₃CH₂CH(CH₃)CH₂Cl at CH₂Cl forms CH₃CH₂CH(CH₃)CH₂⁺ (primary), but a hydride shift forms CH₃CH₂C⁺(CH₃)CH₃ (tertiary), stabilized by the +I effect of three alkyl groups.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
