4 public questions tagged with this topic.
Pent-1-ene (CH₂=CHCH₂CH₂CH₃) reacts with H₂SO₄ and H₂O via acid-catalyzed hydration, adding -OH to the second carbon (Markovnikov’s rule) to form pentan-2-ol.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Preparation of Alcohols - from Alkenes Haloalkanes Carbonyls Grignard
Hydroboration-oxidation of propene (CH₃-CH=CH₂) follows anti-Markovnikov addition, yielding propan-1-ol (CH₃-CH₂-CH₂OH).
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Preparation of Alcohols - from Alkenes Haloalkanes Carbonyls Grignard
Styrene (CH₂=CH-C₆H₅) undergoes acid-catalyzed hydration with H₂SO₄ and H₂O, adding -OH to the more substituted carbon (Markovnikov addition), forming 1-phenylethanol.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Classification and Nomenclature and Structures of Alcohols Phenols Ethers
For 2-pentene ( CH₃CH=CHCH₂CH₃ ), HCl adds via Markovnikov's rule, forming CH₃CHClCH₂CH₂CH₃ (2-chloropentane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
