11 public questions tagged with this topic.
α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/6.8 × 10⁻⁴) ≈ 1.47 × 10⁻¹¹ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰) ≈ 1.61 × 10⁻⁵ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
For HZ H+ + Z- , Ka = (x²/0.1 - x) ≈ (x²/0.1) = 2.0 × 10⁻⁴ . Solving, x² = 2.0 × 10⁻⁵ , x = 4.47 × 10⁻³ , pH = -log(4.47 × 10⁻³) ≈ 2.35 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/1.2 × 10⁻²) = 8.33 × 10⁻¹³ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , so Kb = (Kw/Ka) = (1.0 × 10⁻¹⁴/4.9 × 10⁻¹⁰) ≈ 2.04 × 10⁻⁵ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (Kw/Ka) = (1.0 × 10⁻¹⁴/6.8 × 10⁻⁴) ≈ 1.47 × 10⁻¹¹ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases
Ka = ([H+][A-]/[HA]) = (x²/0.05 - x) ≈ (x²/0.05) = 1.0 × 10⁻⁵ , x² = 5.0 × 10⁻⁷ , x = 7.07 × 10⁻⁴ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant
They have a low Ka value is the scientifically accurate answer to this question. Within the study of Acid, Base, pH, this concept is well-established through extensive research and is documented in standard scientific literature. The specific properties, mechanisms, or characteristics of They have a low Ka value directly address what is being asked. Among the other options, They completely ionize in solution, Their conjugate bases are weak, and They have a high pH do not correctly answer this question because they either refer to different concepts, describe properties of other molecules or processes, or represent common misconceptions about this topic.
Ref: Lehninger Principles of Biochemistry, Nelson & Cox, 8th Ed., Ch. 2
HCl is the scientifically accurate answer to this question. Within the study of Acid, Base, pH, this concept is well-established through extensive research and is documented in standard scientific literature. The specific properties, mechanisms, or characteristics of HCl directly address what is being asked. Among the other options, CH₃COOH, H₂CO₃, and HCN do not correctly answer this question because they either refer to different concepts, describe properties of other molecules or processes, or represent common misconceptions about this topic.
Ref: Lehninger Principles of Biochemistry, Nelson & Cox, 8th Ed., Ch. 2
