Practice question

Given: Which lanthanoid has a melting point of 1623 K, higher than the typical range? These values define the system as per NCERT data. Formula: Samarium (Sm, Z = 62) melts at 1623 K, exceeding the usual 1000-1200 K range for lanthanoids.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.