Skip to content

Question

What is the wavelength of light in a medium with refractive index 1.65 if its wavelength in air is \(
660 \, \text{nm} \)?

Options

Choose one · Correct answer highlighted

Explanation

**Frequency of light** does not change on refraction, c = f λ, when enters denser medium speed decreases, wavelength decreases λ' = v/f = c/(n f) = λ/n, frequency same, for λ=480 nm f=c/λ=3×10⁸/480×10⁻⁹=6.25×10¹⁴ Hz, for 630 nm f=4.76×10¹⁴ Hz, for 540 nm f=5.56×10¹⁴ Hz, refractive index determines bending. Wavelength in a medium λ_m = (λₐir/n) . Given λₐir = 660 nm , n = 1.65 , λ_m = (660/1.65) = 400 nm . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A =

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.