Skip to content

Question

What is the product when C₆H₅NH₂ is treated with excess CH₃Cl in the presence of a base?

Options

Choose one · Correct answer highlighted

Explanation

Aniline ( C₆H₅NH₂ ) with excess CH₃Cl and a base undergoes exhaustive alkylation to form C₆H₅N(CH₃)2 (N, N-dimethylaniline), a tertiary amine. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.