Practice question
Question
What is the product when C₆H₅NH₂ is treated with excess CH₃Cl in the presence of a base?
Explanation
Aniline ( C₆H₅NH₂ ) with excess CH₃Cl and a base undergoes exhaustive alkylation to form C₆H₅N(CH₃)2 (N, N-dimethylaniline), a tertiary amine. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
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