Practice question
Question
The rate law of a reaction is Rate = k[A][B] . If both [A] and [B] are increased by a factor of 3, by what factor does the rate increase?
Explanation
Given:
The rate law of a reaction is Rate = k[A][B] . If both [A] and [B] are increased by a factor of 3, by what factor does the rate increase?
These values define the system as per NCERT data.
Formula:
Initial rate = k[A][B], new rate = k(3[A])(3[B]) = 9k[A][B].
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Factor = 9.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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