Practice question

Given: What is the phase difference corresponding to a path difference of 7lambda/4 in a double-slit experiment? These values define the system as per NCERT data. Formula: Phase difference phi = 2π/lambda Δ. This is standard NCERT relation. Substitution & Calculation: For Δ = 7lambda/4, phi = 2π/lambda · 7lambda/4 = 7π/2 . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.