Skip to content

Question

What is the entropy change (Δ S) for the vaporization of 18 g of water at 373 K if Δ Hvap = 40.79 kJ/mol? (Molar mass of H₂O = 18 g/mol)

Options

Choose one · Correct answer highlighted

Explanation

Moles = 18 / 18 = 1 mol, Δ S = Δ Hvap / T = 40.79 × 10³ / 373 = 109.36 J/K·mol.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.