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Question

Two waves \( y_1 = 6 \sin (4x - 12t) \) and \( y_2 = 6 \sin (4x - 12t + \pi) \) interfere. What is the
amplitude of the resultant wave?

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Choose one · Correct answer highlighted

Explanation

**Superposition principle** states resultant displacement equals algebraic sum of individual waves, y = y₁ + y₂. For coherent waves with phase difference φ, resultant amplitude A = √(a₁² + a₂² + 2a₁a₂ cosφ), equal amplitudes give A = 2a cos(φ/2), constructive when φ = 2nπ, destructive when φ = (2n+1)π. Amplitude: A = 2a cos (Φ/2) , a = 6 m , Φ = π . A = 2 × 6 cos (π/2) = 12 × 0 = 0 m (destructive interference). Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

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