Practice question

**Parallel current interaction** arises because each wire's field B = μ₀ I/(2π d) exerts force F = I l B on other. Force per length f = B I, leading to f = μ₀ I₁ I₂/(2π d). This defines ampere: two wires 1 m apart carrying 1 A exert 2×10⁻⁷ N/m. Force per unit length f = (μ₀ I₁ I₂/2 π d) . f = (4 π × 10⁻⁷ × 10 × 2/2 π × 0.03) = (80 × 10⁻⁷/0.06) = 1.333 × 10⁻⁵ ≈ 1.33 × 10⁻⁵ N/m . Using F = q v B sinθ, F = I l B sinθ, B =