Practice question
Question
The wavenumber of the second line in the Paschen series of a hydrogen atom is: (RH = 1.097 × 10⁷ m⁻¹)
Explanation
Paschen: n₁=3, second line n₂=5. ν̄ = 1.097×10⁷ (1/9 - 1/25) = 7.805×10⁵ m⁻¹.
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