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Question

The uncertainty in velocity of an electron is 1.0 × 10⁶ m s⁻¹. What is the minimum uncertainty in its position? (h = 6.626 × 10⁻³⁴ J s, mₑ = 9.1 × 10⁻³¹ kg)

Options

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Explanation

Δp = m Δv. Δx ≥ h/(4π Δp) ≈ 5.8×10⁻¹¹ m.