Practice question
Question
The frequency of a photon emitted during a transition from n = 6 to n = 3 in a hydrogen atom is: (E₁ = -2.18 × 10⁻¹⁸ J, h = 6.626 × 10⁻³⁴ J s)
Explanation
ΔE = E₆ - E₃ ≈ 1.816×10⁻¹⁹ J. ν = ΔE/h ≈ 2.741×10¹⁴ Hz.
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