9 public questions tagged with this topic.
Transitions: 5→2, 5→3→2, 5→4→2, 4→2, 3→2. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Transitions: 7→4, 7→5→4, 7→6→4, 6→4, 5→4. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
ν̄ = RH (1 - 1/9) = 9.753×10⁶ m⁻¹. λ = 102.5 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
n=4. ΔE ≈ 1.635×10⁻¹⁸ J. ν ≈ 2.467×10¹⁵ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
ν̄ = RH (1/4 - 1/9) = 1.5236×10⁶ m⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
ν̄ = RH (1/4 - 1/16) = 2.057×10⁶ m⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
ΔE = E₆ - E₃ ≈ 1.816×10⁻¹⁹ J. ν = ΔE/h ≈ 2.741×10¹⁴ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
Longest wavelength (lowest energy) for n=4 to n=3.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
E₅ = -77.44/25 ≈ -3.098 eV. IE = 3.098 eV.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
