12 public questions tagged with this topic.
ν̄ = RH (1 - 1/9) = 9.753×10⁶ m⁻¹. λ = 102.5 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Brackett: n₁=4, n₂=6. λ = 2625 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
W₀ = 4.0×10⁻¹⁹ J. λmax = hc/W₀ ≈ 4.97×10⁻⁷ m = 497 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
L = nh/2π, for n=5, L = 5 × 6.626×10⁻³⁴ / (2×3.14) = 5.275×10⁻³⁴ J s.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Wavenumber ν̄ = 4 × 1.097×10⁷ (1/1² - 1/2²) = 3.291×10⁷ m⁻¹. Frequency ν = c ν̄ = 3.0×10⁸ × 3.291×10⁷ = 9.873×10¹⁵ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Number of lines = (8-4)(8-4+1)/2 = 10; actual distinct transitions = 7.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
Orbitals = 9. Each has 2 electrons. Total sets = 18.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
ΔE = E₆ - E₃ ≈ 1.816×10⁻¹⁹ J. ν = ΔE/h ≈ 2.741×10¹⁴ Hz.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
Pfund series: n₁=5, fifth line n₂=10. ν̄ = 1.097×10⁷ (1/25 - 1/100) = 3.291×10⁵ m⁻¹. λ = 1/ν̄ = 3.039×10⁻⁶ m = 3039 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability
For H (Z=1), v₂ = 2.19×10⁶ / 2 = 1.095×10⁶ m s⁻¹. For Li²⁺ (Z=3), v₃ = 3 × 2.19×10⁶ / 3 = 2.19×10⁶ m s⁻¹. Ratio = 0.5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum
r₂ = 4 × r₁ = 2.116×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
v₃ = Z v₁ / n = 2×2.19×10⁶/3 = 1.46×10⁶ m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
