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Practice question

MCQ

Question

How much heat is required to vaporize 0.15kg of nitrogen at −196∘C? (Latent heat of vaporization of nitrogen = 2.0×105J kg−1)

Options

Choose one · Correct answer highlighted

Explanation

Given: m = 0.15kg, Lv = 2.0×105J kg−1. Q = mLv = 0.15×2.0×105 = 30000J = 30kJ. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 30 kJ. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

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