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Question

How much heat is required to raise the temperature of 1 mole of argon gas by 20 K at constant volume? (R = 8.31 J mol⁻¹ K⁻¹)

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Explanation

**Dalton's law of partial pressures** total pressure P_total = Σ P_i, P_i = X_i P_total, X_i mole tion, each gas exerts pressure as if alone, ideal gas mixture P_i V = n_i R T, partial pressure proportional to mole tion, e.g., air 79% N₂ 21% O₂ P_N₂=0.79 atm P_O₂=0.21 atm at 1 atm total. For monatomic gas, C_v = (3)/(2) R.Heat Q = μ C_v Δ T = 1 × (3)/(2) × 8.31 × 20 = 249.3 J ≈ 249 J . Substituting values gives 249 J, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas

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