4 public questions tagged with this topic.
For a diatomic ideal gas at constant volume, Δ U = qv = nCvΔ T . Given qv = 208 J , n = 1 mol , Δ T = 310 - 300 = 10 K , we get 208 = 1 × Cv × 10 , so Cv = 208 / 10 = 20.8 J/mol·K , typical for a diatomic gas ( Cv ≈ 2.5R ).
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Thermodynamic Terms - System Surroundings and Types of Systems
At constant volume, w = -pΔ V = 0, so from the first law, Δ U = qv, the heat absorbed at constant volume.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: First Law of Thermodynamics and Enthalpy and Internal Energy
At constant volume, w = -PΔ V = 0. First Law: Δ U = q + w = 600 + 0 = 600 J, so w = 0 J.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: First Law of Thermodynamics and Enthalpy and Internal Energy
Volume correctly identifies the characteristic feature or property described in this question. In Thermodynamics, specific characteristics define and distinguish biological molecules, organisms, or processes from one another. The feature described by Volume is a defining property that arises from its unique molecular structure, evolutionary history, or physiological role. The other options (Pressure, Temperature, and Enthalpy) describe characteristics of different entities, represent incorrect properties, or apply to the subject under different conditions.
Ref: Lehninger Principles of Biochemistry, Nelson & Cox, 8th Ed., Ch. 1
