Practice question
Question
How much heat is required to melt 0.3kg of ice at 0∘C to water at 0∘C? (Latent heat of fusion = 3.33×105J kg−1)
Explanation
Given: m = 0.3kg, Lf = 3.33×105J kg−1. Q = mLf = 0.3×3.33×105 = 99900J = 99.9kJ. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 99.9 kJ. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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