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Question

How many coulombs are required to deposit 0.81 g of magnesium from MgSO₄ solution? (Atomic mass of Mg = 24 g/mol, F = 96500 C/mol)

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Explanation

Mg²⁺ + 2e⁻ → Mg . 1 mol Mg (24 g) requires 2F. Moles = (0.81/24) = 0.03375 mol , Charge = 0.03375 × 2 × 96500 = 6513.75 C .

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