Practice question

For a rod pivoted at its center: I = 112ML2. M = 5kg, L = 2m. I = 112×5×(2)2 = 2012 = 53≈1.67kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.67 kg m². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.