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Question

A stationary wave on a string fixed at both ends has a frequency of 120 Hz and a wave speed of 48 m/s.
What is the length of the string?

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Explanation

**Superposition principle** states resultant displacement equals algebraic sum of individual waves, y = y₁ + y₂. For coherent waves with phase difference φ, resultant amplitude A = √(a₁² + a₂² + 2a₁a₂ cosφ), equal amplitudes give A = 2a cos(φ/2), constructive when φ = 2nπ, destructive when φ = (2n+1)π. Fundamental: v₁ = (v/2L) . 120 = (48/2L) ⇒ 2L = (48/120) ⇒ 2L = 0.4 ⇒ L = 0.2 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.2 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

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