Practice question
Question
A solution of two volatile liquids has vapor pressures of 500 mm Hg and 700 mm Hg. If the total vapor pressure is 580 mm Hg, what is the mole fraction of the first component in the vapor phase?
Explanation
Liquid phase: 580 = 500 x₁ + 700 (1 - x₁) . 580 = 500 x₁ + 700 - 700 x₁ , 200 x₁ = 120 , x₁ = 0.6 , x₂ = 0.4 . Vapor phase: y₁ = (500 × 0.6/580) ≈ 0.5172 .
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