21 public questions tagged with this topic.
Mole fraction of water = 1 - 0.1 = 0.9 . Vapor pressure = 50 × 0.9 = 45 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Raoult’s law: P = P₁⁰ · x₁ + P₂⁰ · (1 - x₁) . P = 400 × 0.6 + 600 × 0.4 = 240 + 240 = 480 mm Hg . Actual = 520 mm Hg ≠ 480 mm Hg, so it does not obey Raoult’s law.
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Mole fraction of methanol = 1 - 0.3 = 0.7 . Vapor pressure = 90 × 0.7 = 63 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Mole fraction of second = 1 - 0.6 = 0.4 . Total vapor pressure = 250 × 0.6 + 350 × 0.4 = 150 + 140 = 290 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Pure P₁⁰ = 400 mm Hg . In solution: P₁ = P₁⁰ · x₁ = 400 × 0.5 = 200 mm Hg . Vapor pressure lowering = P₁⁰ - P₁ = 400 - 200 = 200 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Liquid phase: 310 = 250 x₁ + 350 (1 - x₁) . 310 = 250 x₁ + 350 - 350 x₁ , 100 x₁ = 40 , x₁ = 0.4 , x₂ = 0.6 . Vapor phase: y₁ = (P₁⁰ · x₁/Ptotal) = (250 × 0.4/310) ≈ 0.3226 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Mole fraction of water = 1 - 0.25 = 0.75 . Vapor pressure = 24 × 0.75 = 18 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Mole fraction of solvent = 1 - 0.25 = 0.75 . Vapor pressure = 40 × 0.75 = 30 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
P = P₁⁰ · x₁ + P₂⁰ · x₂ , where x₁ + x₂ = 1 . 216 = 180 (1 - x₂) + 240 x₂ . 216 = 180 - 180 x₂ + 240 x₂ . 216 - 180 = 60 x₂ , x₂ = (36/60) = 0.6 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
(p⁰ - p/p⁰) = xsolute . (25 - 22/25) = (3/25) = 0.12 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
(p⁰ - p/p⁰) = xsolute . (40 - 38/40) = (2/40) = 0.05 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
Total vapor pressure = p₁⁰ · x₁ + p₂⁰ · x₂ . 300 × 0.4 + 400 × 0.6 = 120 + 240 = 360 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
