Practice question
Question
A solution is prepared by dissolving 15 g of a non-volatile solute in 300 g of water. If the freezing point depression is 0.465°C and Kf = 1.86 K kg mol⁻¹ , what is the molar mass of the solute?
Explanation
Δ Tf = Kf · m . 0.465 = 1.86 × (moles/0.3) . Moles = (0.465 × 0.3/1.86) ≈ 0.075 . Molar mass = (15/0.075) = 200 g/mol .
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