Practice question
Question
The osmotic pressure of a solution containing 5 g of a solute in 1 L of solution at 27°C is 2.46 atm. What is the molar mass of the solute? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = (n/V) RT , n = (w/M) . 2.46 = (5/M) × 0.0821 × 300 . M = (5 × 0.0821 × 300/2.46) ≈ 50 g/mol .
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