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Question

A solution contains 0.05 mole of a gas dissolved in 1 kg of water at a partial pressure of 10 bar. If the temperature changes and the solubility doubles, what is the new Henry’s law constant?

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Explanation

Initial: 10 = KH · 0.05 , KH = 200 bar . New solubility = 0.1 mol/kg at same pressure. 10 = KH' · 0.1 , KH' = 100 bar .

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