Practice question
Question
A solenoid with 700 turns per meter carries a current of \( 2 \, \text{A} \). What is the magnetic
intensity \( H \) inside?
Explanation
**Solenoid with magnetic core** produces field B = μ₀ μ_r n I inside, μ₀ = 4π×10⁻⁷ T·m/A, μ_r relative permeability, n = N/L turns per meter, I current. Core enhances field μ_r times, so given B, μ_r, n, current I = B/(μ₀ μ_r n) can be found, illustrating core effect on field strength. Magnetic intensity H = n I . Given: n = 700 m⁻¹ , I = 2 A . Substitute: H = 700 × 2 = 1400 A m⁻¹ . Substituting values gives 1400 A m⁻¹, which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.
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