Practice question
Question
A satellite orbits Earth at 19RE from the center. What is its orbital speed? (g\=9.8m/s2,RE\=6.4×106m)
Explanation
v = gRE2r. r = 19RE, v = 9.8×6.4×10619. v = 3.301×106≈1.82×103m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.8 × 10³ m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
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