Practice question
Question
A lead storage battery is discharged with 2 A for 5 hours. What is the mass of PbO₂ (molar mass 239 g/mol) consumed at the cathode? (F = 96500 C/mol)
Explanation
Charge = 2 × 5 × 3600 = 36000 C . Cathode: PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ → PbSO₄ + 2H₂O . 1 mol PbO₂ requires 2F. Faradays = (36000/96500) = 0.373 F , Moles = (0.373/2) = 0.1865 mol , Mass = 0.1865 × 239 = 44.57 g .
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