Practice question
Question
A lead storage battery delivers 1.5 A for 10 hours during discharge. How many grams of PbSO₄ (molar mass 303 g/mol) are formed at the anode? (F = 96500 C/mol)
Explanation
Charge = 1.5 × 10 × 3600 = 54000 C . Anode: Pb + SO₄²⁻ → PbSO₄ + 2e⁻ . 1 mol PbSO₄ requires 2F. Faradays = (54000/96500) = 0.5596 F , Moles = (0.5596/2) = 0.2798 mol , Mass = 0.2798 × 303 = 84.78 g .