Practice question
Question
A hydrogen electrode operates at 298 K with PH_₂ = 0.5 atm and pH = 3. What is its potential? (Given: E°H⁺/H_₂ = 0.00 V )
Explanation
E = E° - (0.059/2) log (PH_₂/[H⁺]²) , [H⁺] = 10⁻³ . E = 0 - 0.0295 log (0.5/10⁻⁶) = 0 - 0.0295 × 5.301 = -0.1564 V .
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