Practice question
Question
A glass rod loses \( 6.4 \times 10^{-8} \, \text{C} \) of charge when rubbed with silk. How many
electrons were transferred from it?
Explanation
**Quantization of charge** states observable charge is integer multiple of elementary charge e = 1.6×10⁻¹⁹ C, q = n·e, and total charge is conserved in isolated systems. Loss of electrons produces positive charge, and number of transferred electrons follows n = q/e, linking macroscopic charge measurement to microscopic carriers. Losing charge means electrons are removed, so charge is positive. q = n e , e = 1.6 × 10⁻¹⁹ C . n = (q/|e|) = (6.4 × 10⁻⁸/1.6 × 10⁻¹⁹) = 4 × 10¹¹ . Substituting values gives 4 × 10¹¹, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.
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