Practice question
Question
A gas at 2.4atm and 87∘C occupies 7L. If the temperature is lowered to 37∘C and pressure adjusted to 3atm, what is the percentage change in volume?
Explanation
Given: P1 = 2.4atm, T1 = 87∘C = 360K, V1 = 7L, T2 = 37∘C = 310K, P2 = 3atm. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 7×2.43×310360 = 7×0.8×0.8611≈4.82L. Percentage change: V1−V2V1×100 = 7−4.827×100 = 2.187×100≈31.14% (decrease).
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