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Question

A gas at 1.9atm and 67∘C occupies 6.5L. If the pressure is increased to 2.5atm and temperature raised to 117∘C, what is the new volume?

Options

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Explanation

Given: P1 = 1.9atm, T1 = 67∘C = 340K, V1 = 6.5L, P2 = 2.5atm, T2 = 117∘C = 390K. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 6.5×1.92.5×390340 = 6.5×0.76×1.1471≈5.66L.