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Question

A gas at 1.5atm and 77∘C occupies 9L. If the pressure is reduced to 1atm and temperature lowered to 27∘C, what is the new volume?

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Explanation

Given: P1 = 1.5atm, T1 = 77∘C = 350K, V1 = 9L, P2 = 1atm, T2 = 27∘C = 300K. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 9×1.51×300350 = 9×1.5×0.8571≈11.57L.

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