Practice question
Question
A conductivity cell with cell constant 0.5 cm⁻¹ shows a resistance of 200 Ω with a 0.02 M KCl solution. What is the molar conductivity of the solution?
Explanation
kappa = (cell constant/R) = (0.5/200) = 0.0025 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0025 × 1000/0.02) = 125 S cm² mol⁻¹ .
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