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Question

How many coulombs are required to deposit 2.07 g of lithium from a LiCl solution? (Atomic mass of Li = 6.9 g/mol, F = 96500 C/mol)

Options

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Explanation

Li⁺ + e⁻ → Li . 1 mol Li (6.9 g) requires 1F. Moles = (2.07/6.9) = 0.3 mol , Charge = 0.3 × 96500 = 28950 C .