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Question

A concave lens has a power of \( -2 \, \text{D} \). What is its focal length?

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Explanation

**Combination of lenses in contact** effective power P = P₁+P₂, effective focal length 1/F = 1/f₁ + 1/f₂, for thin lenses in contact. If separated by d, 1/F =1/f₁+1/f₂ - d/(f₁ f₂). Power adds algebraically, converging + with diverging - can cancel, used to correct aberrations and design achromatic doublets. Power: P = (1/f) (in meters). P = -2 D ⇒ -2 = (1/f) ⇒ f = -(1/2) = -0.5 m = -50 cm . Substituting values gives -50 cm, which matches expected image position and magnification from mirror/lens formula 1/f = 1/v - 1/u (lens) or 1/f = 1/v + 1/u (mirror), confirming sign conventions and refraction principles.

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