Practice question
Question
A car traveling at 54km/h comes to rest in 10s with uniform deceleration. What is the magnitude of the deceleration?
Explanation
Convert speed: 54km/h=54⋅10003600=15m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 1.5 m/s² as the result, so option A is correct.