A 6kg block slides down a frictionless incline from 10m height. What is its speed at the bottom? (Take g\=10m/s2)
Potential energy mgh=6×10×10=600J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 600 J. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Laws of Motion and Energy Conservation