Practice question

Given: A particle accelerates uniformly from rest to 20 m/s in 5 s . What is the distance covered? These values define the system as per NCERT data. Formula: Find a = v - v_0/t = 20 - 0/5 = 4 m/s². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Use x = v_0 t + 1/2 a t² = 0 · 5 + 1/2 · 4 · (5)² = 0 + 2 · 25 = 50 m . The distance covered is 50 m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.