Practice question
Question
A bike moving at 108km/h comes to rest in 9s with uniform deceleration. What is the magnitude of deceleration?
Explanation
Convert speed: 108km/h=108⋅10003600=30m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 3.3 m/s² as the result, so option A is correct.
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