Practice question
Question
A ball is thrown horizontally from a tower with a speed of 8m/s. It lands 24m from the base. What is the height of the tower? (Take g\=10m/s2)
Explanation
Horizontal distance x=vxt, so t=xvx=248=3s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 45 m as the result, so option A is correct.
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