Practice question
Question
A 4kg block at 9m/s encounters a force F\=−1.5xN from x\=0.6m to x\=3m. What is the final speed?
Explanation
Initial K=12×4×92=162J. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 162 J as the result, so option A is correct.